Given V=V= Constant (i) C′=d′ε0A,C=dε0Ad′′<dC′\gtC Hence, final capacitance greater than initial capacitance, (ii) U′UU′′=21C′V2=21CV2\gtU Hence final energy is greater than initial energy (iii) V′Q′=C′ and VQ=CV′Q′=VQ (iv) Product of charge and voltage X′=Q′V=C′V2X=QV=CV2X′\gtX