
Divided into 10 parts RR′RSRSRPReq =Aρl=10Aρl=10R=5×10R [series] =50=50R [parallel] =RS+RP=52Ω
NEET UG 2024 — Physics Electromagnetism
A wire of length ' 1 and resistance 100Ω is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
Held on 30 Apr 2024 · Verified 9 Jul 2026.
52Ω
55Ω
60Ω
26Ω
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