For case - I ⇒εs=ϕ×330⇒ϕ=330εs( cmV)… For case - II ⇒i×2=ϕI2⇒3εs×2=330εs×I2 [From equation 1] ⇒I2=220 cm
The emf of a cell having internal resistance 1 Ω is balanced against a length of 330 ~cm on a potentiometer wire. When an external resistance of 2 Ω…
NEET UG 2023 — Physics Electromagnetism
2023mcqmedium
The emf of a cell having internal resistance 1Ω is balanced against a length of 330 cm on a potentiometer wire. When an external resistance of 2Ω is connected across the cell, the balancing length will be
Official previous-year question
Held on 30 Apr 2023 · Verified 9 Jul 2026.
Options
- A
115 cm
- B
332 cm
- C
220 cm
- D
330 cm
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