Frequency of oscillation =2×1010Hz
Given c=3×108ms−1,
Electric field amplitude E0=48Vm−1
Using the formula, c=B0E0
The amplitude of the oscillating magnetic field
B0=cE0=3×10848=1.6×10−7T.
NEET UG 2023 — Physics Electromagnetism
In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2.0×1010Hz and amplitude 48Vm−1. Then the amplitude of oscillating magnetic field is: (Speed of light in free space =3×108ms−1)
Held on 30 Apr 2023 · Verified 9 Jul 2026.
1.6×10−6T
1.6×10−9T
1.6×10−8T
1.6×10−7T
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