we know F=mgIℓB=mg I=ℓBmg=(2)(0.7)250×10−3×9.8 I=1750×10−3 AI=1.75 A
A long straight wire of length 2 m and mass 250 g is suspended horizontally in a uniform horizontal magnetic field of 0.7 T. The amount of current flowing through the wire will be (g=9.8 ms−2)
Held on 30 Apr 2023 · Verified 9 Jul 2026.
2.75 A
1.75 A
2.45 A
2.25 A
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