The given diagram can be redrawn as follow:
The potential across AC, VAC=RBC+RACRAC×V0 43R0+4R+R0RR04R+R0RR0×V0=3R0+16R4RV0
NEET UG 2022 — Physics Electromagnetism
The sliding contact C is at one fourth of the length of the potential wire (AB) from A as shown in the circuit diagram. If the resistance of the wire AB is R0, then the potential drop (V) across the resistor R is: 
Held on 30 Apr 2022 · Verified 9 Jul 2026.
3R0+16R4 V0R
3R0+R4V0R
4R0+R2V0R
2R0+3R2V0R
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
Two point charges +2μC and -2μC are placed 10 cm apart. The electric field at the midpoint is:
A parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant rate with time. The magnetic field arising due to displacement current is :
Two identical charged conducting spheres $A$ and $B$ have their centres separated by a certain distance. Charge on each sphere is q and the force of repulsion between them is $F$. A third identical uncharged conducting sphere is brought in contact with sphere A first and then with B and finally removed from both. New force of repulsion between spheres $A$ and $B$ (Radii of $A$ and $B$ are negligible compared to the distance of separation so that for calculating force between them they can be considered as point charges) is best given as :
The electric potential at distance r from a point charge q is V = q/(4πε₀r). The electric field E is:
The current passing through the battery in the given circuit, is : 
Work through every NEET UG Electromagnetism PYQ, year by year.