Given: ϕ=2t3+4t2+2t+5, & t=5 s By Faraday's law of EMI, we have, emf=−dtdϕ (where, the symbols have their usual meanings) e=dtdϕ=dtd(2t3+4t2+2t+5)=6t2+8t+2 extAtte=5s=6(5)2+8(5)+2=192 V
NEET UG 2022 — Physics Electromagnetism
The magnetic flux linked to a circular coil of radius R is: ϕ=2t3+4t2+2t+5 Wb The magnitude of induced emf in the coil at t=5 s is:
Held on 30 Apr 2022 · Verified 9 Jul 2026.
108 V
197 V
150 V
192 V
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