
V=VR2+(VC−VL)2
=402+(10−40)2
=50volt
irms=ZVrms
⇒Z=irmsvrms
⇒Z=10Vrms×2
⇒Z=1022×50
⇒Z=5Ω
An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance R are connected in series to an ac source of potential difference V volt as shown in figure.Potential difference across L,C and R is 40V,10V and 40V, respectively. The amplitude of current flowing through L-C-R series circuit is 102A. The impedance of the circuit is :

Held on 30 Apr 2021 · Verified 9 Jul 2026.
42Ω
5/2Ω
5Ω
4Ω
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