L=5H,C=80μF,R=40ω;V=230V
Resonance angular frequency =ω0=LC1=5×(80×10−6)1=50rads−1
Half power angular frequency =ω0±2LR=50±2×540=50±4=54or46
We get,
ω1=46rads−1
And ω2=54rads−1
NEET UG 2021 — Physics Electromagnetism
A series L−C−R circuit containing 5.0H inductor, 80μF capacitor and 40Ω resistor is connected to 230V variable frequency ac source. The angular frequencies of the source at which power transferred to the circuit is half the power at the resonant angular frequency are likely to be:
Held on 30 Apr 2021 · Verified 9 Jul 2026.
25rads−1and75rads−1
50rads−1 and 25rads−1
46rads−1 and 54rads−1
42rads−1 and 58rads−1
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