A seriesLCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is π…
NEET UG 2020 — Physics Electromagnetism
2020mcqeasy
A seriesLCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is 3π. If instead C is removed from the circuit, the phase difference is again 3π between current and voltage. The power factor of the circuit is:
Official previous-year question
Held on 30 Apr 2020 · Verified 9 Jul 2026.
Options
A
0.5
B
1.0
C
–1.0
D
zero
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Solution
As phase angle contribution by capacitor and inductor are equal in magnitude, so XL=Xc⇒ωL=ωC1 It means that the RLC circuit is in resonance condition. So, impedance at resonance, Z=R2+(XL−XC)2=R2+(XL−XL)2=R2=R Thus, power factor, cosϕ=ZR=RR=1
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