q=CV
dtdq=Cdtdv
=20×10−6×3
Conduction current =60μA
Displacement current =ϵ0dtdϕe
=ϵ0dAdtdV
=60μA
NEET UG 2019 — Physics Electromagnetism
A parallel plate capacitor of capacitance 20 μF is being charged by a voltage source whose potential is changing at the rate of 3Vs−1. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor would be, respectively:
Held on 30 Apr 2019 · Verified 9 Jul 2026.
zero,60μA
60μA,60μA
60μA, zero
zero, zero
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