For current I through an inductor coil having inductance L , Magnetic potential energy stored in the inductor is given by
U=21LI2
Given
U=25 mJ=25×10−3 J
I=60 mA =60×10−3 A
∴25×10−3=21L(60×10−3)2
Solving L=13.89H
NEET UG 2018 — Physics Electromagnetism
The magnetic potential energy stored in a certain inductor is 25mJ, when the current in the inductor is 60mA . This inductor is of inductance
Held on 30 Apr 2018 · Verified 9 Jul 2026.
1.389H
138.88H
0.138H
13.89H
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