F1=2π2Lμ0IiL=πμ0Ii
F2=2π23Lμ0IiL=3πμ0Ii

∴Fnet=F1−F2
Fnet=32πμ0Ii
NEET UG 2016 — Physics Electromagnetism
A square loop ABCD carrying a current i, is placed near and coplanar with a long straight conductor XY carrying a current I, the net force on the loop will be:

Held on 30 Apr 2016 · Verified 9 Jul 2026.
3π2μ0Ii
2πμ0Ii
3π2μ0IiL
2πμ0IiL
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