as E∝L
E1−E2E1+E2=λ10λ50
E1+E2=5E1−5E2
6E2=4E1
23=E2E1
A potentiometer wire is 100cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50cm and 10cm from the positive end of the wire in the two cases. The ratio of EMF's is :
Held on 30 Apr 2016 · Verified 9 Jul 2026.
5 : 1
5 : 4
3 : 4
3 : 2
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