V=6xy−y+2yz
E=−(∂x∂Vi^+∂y∂Vj^∂z∂Vk^)
E=−[(6y)i^+(6x−1+2z)j^+(2y)k^]
E(1,1,0)=−(6i^+5j^+2k^)
NEET UG 2015 — Physics Electromagnetism
If potential(in volts) in a region is expressed as V(x,y,z)=6xy−y+2yz, the electric field(in NC−1) at point(1,1,0) is
Held on 30 Apr 2015 · Verified 9 Jul 2026.
−(6i^+5j^+2k^).
−(2i^+3j^+k^).
−(6i^+9j^+k^).
−(3i^+5j^+3k^).
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