τ=M×B=MBsin60o
=NiABsin60o
=50×2×0.12×0.1×0.2×23
=123×10−2Nm=0.20748Nm
NEET UG 2015 — Physics Electromagnetism
A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 Weber/m2 . The coil carries a current of 2A. If the plane of the coil is inclined at an angle of 30o with the direction of the field, the torque required to keep coil in stable equilibrium will be:
Held on 30 Apr 2015 · Verified 9 Jul 2026.
0.20Nm
0.24Nm
0.12Nm
0.15Nm
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