
For air K=1,
C1=C
q=C1V…(i).
The charge remains constant.
U1=2Cq2
U2=2CKq2
Change in energy stored in the capacitor,
U=U2−U1
=2Cq2(K1−1)=21CV2(K1−1)
V′=CKq⇒V′=KV
Here,1- Potential difference between the plates decreases by K times.
2- The change in energy stored ΔU=21CV2(K1−1).
3- Charge is conserved.
4- The energy stored in capacitor decrease by K,U2=21CKq2.