NEET UG 2014 — Physics Electromagnetism

2014mcqeasy

In an ammeter $0.2%$ of main current passes through the galvanometer. If resistance of galvanometer is $G,$ the resistance of ammeter will be:

Official previous-year question

Held on 30 Apr 2014 · Verified 9 Jul 2026.

Options

A
$\frac{1}{499}G$
B
$\frac{499}{500}G$
C
$\frac{1}{500}G$
D
$\frac{500}{499}G$

Did you get this right?

Solution

As shown in figure a shunt $S$ is connected in parallel with the galvanometer to convert it into the ammeter, let $G$ is the resistant of the galvanometer. Where $I$ is the current in the circuit as shown, according to question $0\cdot 2%$ current passing through the galvanometer, i.e.,

NEET 2014 Physics, Current Electricity — solution figure

${I}_{G}=0\cdot 2%ofI=\frac{0\cdot 2}{100}I=\frac{I}{500}$ ;

so, the current through the shunt is $I={I}_{G}+{I}_{S}\Rightarrow {I}_{S}=I-{I}_{G} \Rightarrow {I}_{S}=I-\frac{1}{500}=\frac{499}{500}I$

As $(G)$ and the shunt $(S)$ are in parallel combination ,

${V}_{G}={V}_{S}$

${i}_{g}{R}_{g}={i}_{s}{R}_{s}\Rightarrow (\frac{i}{500})(G)=(\frac{499}{500}i)(S)$

$\Rightarrow S=\frac{G}{499}$

Equivalent resistance of the ammeter

$\frac{1}{{R}_{eq}}=\frac{1}{G}+\frac{1}{\frac{G}{499}}\Rightarrow {R}_{eq}=\frac{G}{500}$

Your note

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NEET UG 2014 — Physics Electromagnetism

2014mcqeasy

In an ammeter $0.2%$ of main current passes through the galvanometer. If resistance of galvanometer is $G,$ the resistance of ammeter will be:

Official previous-year question

Held on 30 Apr 2014 · Verified 9 Jul 2026.

Options

A
$\frac{1}{499}G$
B
$\frac{499}{500}G$
C
$\frac{1}{500}G$
D
$\frac{500}{499}G$

Did you get this right?

Solution

NEET 2014 Physics, Current Electricity — solution figure

${I}_{G}=0\cdot 2%ofI=\frac{0\cdot 2}{100}I=\frac{I}{500}$ ;

so, the current through the shunt is $I={I}_{G}+{I}_{S}\Rightarrow {I}_{S}=I-{I}_{G} \Rightarrow {I}_{S}=I-\frac{1}{500}=\frac{499}{500}I$

As $(G)$ and the shunt $(S)$ are in parallel combination ,

${V}_{G}={V}_{S}$

${i}_{g}{R}_{g}={i}_{s}{R}_{s}\Rightarrow (\frac{i}{500})(G)=(\frac{499}{500}i)(S)$

$\Rightarrow S=\frac{G}{499}$

Equivalent resistance of the ammeter

$\frac{1}{{R}_{eq}}=\frac{1}{G}+\frac{1}{\frac{G}{499}}\Rightarrow {R}_{eq}=\frac{G}{500}$

NEET UG 2014 — Physics Electromagnetism

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Solution

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NEET UG 2014 — Physics Electromagnetism

Options

Did you get this right?

Solution

Your note

NEET UG Electromagnetism in other years

More NEET UG Electromagnetism questions

Other Physics topics for NEET UG

Mechanics

Modern Physics

Thermodynamics

Optics

Waves & Oscillations

Keep practicing Electromagnetism