Initial acceleration, a0=m∂E ⇒E=ea0m∴mev0B+eE=3a0 or ev0B+eE=3a0m∴ev0B=3ma0−eE⇒=3ma0−ma0[ fromeq. (i)] ⇒ev0B=2ma0∴B=ev02ma0
NEET UG 2013 — Physics Electromagnetism
When a proton is released from rest in a room, it starts with an initial acceleration a0 towards west. When it is projected towards north with a speed v0 it moves with an initial acceleration 3a0 towards west. The electric and magnetic fields in the room are
Held on 30 Apr 2013 · Verified 9 Jul 2026.
ema0 west, ev02ma0 up
ema0 west, ev02ma0 down
ema0 east, ev03ma0 up
ema0 east ev03ma0 down
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