From the question Velocity of electron =107 m/s Magnetic field B=2×10−4 Wb/m2 
Then magnitude of force experienced by the electron i.e. F=ev Bsinθ {∵V and B are prependicular to each other =ev Bsin90∘=1.6×10−19×107×2×10−4×1=3.2×10−16 N
NEET UG 2013 — Physics Electromagnetism
A long straight wire carries a certain current and produces a magnetic field 2×10−4m2 Weber at a perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire moves with a velocity 107 m/s towards the wire along perpendicular to it. The force experienced by the electron will be (change on electron 1.6×10−19C )
Held on 30 Apr 2013 · Verified 9 Jul 2026.
3.2 N
3.2×10−16 N
1.6×10−16 N
Zero
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