Two positive ions each carrying a charge q are kept at a distance d, then it is found that force of repulsion between them is F=d2kqq=4πε01 d2qq where where ∴⇒q=neF=4πε01 d2n2e2n=e24πε0Fd2
NEET UG 2010 — Physics Electromagnetism
Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, the number of electrons missing from each ion will be ( e being the charge on an electron)
Held on 30 Apr 2010 · Verified 9 Jul 2026.
e24πε0Fd2
d24πε0Fe2
e24πε0Fd2
q24πε0Fd2
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