The electric field of electromagnetic wave E=10cos(107t±kx)j^ Amplitude =10 V/m∵c=kω∴3×108=k107 or k=301 or λ2π=301 or λ=188.4 m So, (1) and (3) option are correct.
The electric field of an electromagnetic wave in free space is given by E=10 cos (10^7 t+k x ) j V / m, where t and x are in seconds and metres…
NEET UG 2010 — Physics Electromagnetism
The electric field of an electromagnetic wave in free space is given by E=10cos(107t+kx)j^V/m, where t and x are in seconds and metres respectively. It can be inferred that (1) The wavelength λ is 188.4 m. (2) The wave number k is 0.33rad/m. (3) The wave amplitude is 10 V/m. (4) The wave is propagating along.t x direction Which one of the following pairs of statements is correct?
Held on 30 Apr 2010 · Verified 9 Jul 2026.
Options
- A
(3) and (4)
- B
(1) and (2)
- C
(2) and (3)
- D
(1) and (3)
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