The magnetic field at centre O for each semicircular parts each of radius R, B1=B2=4Rμ0i The magnetic field at their common centre B B B=B1+B2=B12+B22=(4Rμ0i)2+(4Rμ0i)2=22Rμ0i
NEET UG 2010 — Physics Electromagnetism
A current loop consists of two identical semicircular parts each of radius R, one lying in the x−y plane and the other in x−z plane. If the current in the loop is i. The resultant magnetic field due to the two semicircular parts at their common centre is
Held on 30 Apr 2010 · Verified 9 Jul 2026.
22Rμ0i
2Rμ0i
4Rμ0i
2Rμ0i
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