NEET UG 2009 — Physics Electromagnetism
The magnetic force acting on a charged particle of charge −2μC in a magnetic field of 2 T acting in y direction, when the particle velocity is (2i^+3j^)×106 ms−1 is
Held on 30 Apr 2009 · Verified 9 Jul 2026.
8 N in −z direction
4 N in z direction
8 N in y direction
8 N in z direction
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Two point charges +2μC and -2μC are placed 10 cm apart. The electric field at the midpoint is:
A parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant rate with time. The magnetic field arising due to displacement current is :
Two identical charged conducting spheres $A$ and $B$ have their centres separated by a certain distance. Charge on each sphere is q and the force of repulsion between them is $F$. A third identical uncharged conducting sphere is brought in contact with sphere A first and then with B and finally removed from both. New force of repulsion between spheres $A$ and $B$ (Radii of $A$ and $B$ are negligible compared to the distance of separation so that for calculating force between them they can be considered as point charges) is best given as :
The electric potential at distance r from a point charge q is V = q/(4πε₀r). The electric field E is:
The current passing through the battery in the given circuit, is : 
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