F=q(v×B)=−2×10−6[(2i^+3j^)×106×2j^]=−(8 N)k^
NEET UG 2009 — Physics Electromagnetism
The magnetic force acting on a charged particle of charge −2μc in a magnetic field of 2 T acting in y direction, when the particle velocity is (2i^+3j^)×106 ms−1, is :
Held on 30 Apr 2009 · Verified 9 Jul 2026.
8 N in z - direction
8 N in z− direction
4 N in z - direction
8 N in y− direction
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