VE=−x2y−xz3+4=−V=−(i^δxδ+j^δyδ+k^δzδ)=(2xy+z3)i^+x2j^+3xz2+4)
NEET UG 2009 — Physics Electromagnetism
The electric potential at a point (x,y,z) is given by V=−x2y−xz3+4 The electric field E at that point is :
Held on 30 Apr 2009 · Verified 9 Jul 2026.
E=i^(2xy−z3)+j^xy2+k^3z2x
E=i^(2xy+z3)+j^x2+k^3xzz2
E=i^2xy+j^(x2+y2)+k^(3xz−y2)
E=i^z+j^xyz+k^z2
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