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The electric potential at a point (x, y, z) is given by V=-x^2 y-x z^3+4 The electric field overrightarrow E at that point is :

NEET UG 2009 — Physics Electromagnetism

2009mcqhard

The electric potential at a point (x,y,z)(x, y, z)(x,y,z) is given by V=−x2y−xz3+4\mathrm{V}=-x^2 y-x z^3+4V=−x2y−xz3+4 The electric field E→\overrightarrow{\mathrm{E}}E at that point is :

Official previous-year question

Held on 30 Apr 2009 · Verified 9 Jul 2026.

Options

  1. A

    E⃗=i^(2xy−z3)+j^xy2+k^3z2x\vec{E}=\hat{i}\left(2 x y-z^3\right)+\hat{j} x y^2+\hat{k} 3 z^2 xE=i^(2xy−z3)+j^​xy2+k^3z2x

  2. B

    E→=i^(2xy+z3)+j^x2+k^3xzz2\overrightarrow{\mathrm{E}}=\hat{\mathrm{i}}\left(2 x y+\mathrm{z}^3\right)+\hat{\mathrm{j}} \mathrm{x}^2+\hat{\mathrm{k}} 3 \mathrm{xz} \mathrm{z}^2E=i^(2xy+z3)+j^​x2+k^3xzz2

  3. C

    E⃗=i^2xy+j^(x2+y2)+k^(3xz−y2)\vec{E}=\hat{i} 2 x y+\hat{j}\left(x^2+y^2\right)+\hat{k}\left(3 x z-y^2\right)E=i^2xy+j^​(x2+y2)+k^(3xz−y2)

  4. D

    E→=i^z+j^xyz+k^z2\overrightarrow{\mathrm{E}}=\hat{\mathrm{i}} z+\hat{\mathrm{j}} x y z+\hat{\mathrm{k}} z^2E=i^z+j^​xyz+k^z2

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