Comparing the given equation Ey=2.5CNcos[(2π×106mrad)t−(π×10−2secrad)x] With the standard equation Ey=E0cos(ωt−kx) we get ∴ω=2πf=2π×106f=106 Hz Moreover, we know that ⇒λ2π⇒λ=k=π×10−2 m−1=200 m Hence, the wave is moving along positive x-direction with frequency 106 Hz and wavelength 200 m.