W=MB(cosθ1−cosθ2)=2×104×6×10−4(cosθ−cos60∘)=12×21=6 J
NEET UG 2009 — Physics Electromagnetism
A bar magnet having a magnetic movement of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B=6×10−4 T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60∘ from the field is :
Held on 30 Apr 2009 · Verified 9 Jul 2026.
2 J
0.6 J
12 J
6 J
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