Key Idea : In parallel resistances, potential difference across them is same. Potential difference across PM V=4×1=4 volt (ie, across 4Ω) Equivalent resistance of lower side arm, Req=1+0.5+0.50.5×0.5=1.25Ω Now the circuit can be shown as
Let current I flows in lower branch, so 1.25II=4 V=1.254=3.2 A Therefore, 3.2 A current flows in 1Ω resistance, hence potential difference between M and N is V′=3.2×1=3.2 volt
