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In an A C circuit the emf (e) and the current (i) at any instant are given respectively by e=E_0 sin ω t i=I_0 sin (ω t-φ) The average power in the…

NEET UG 2008 — Physics Electromagnetism

2008mcqeasy

In an ACA CAC circuit the emf (e) and the current (i) at any instant are given respectively by e=E0sin⁡ωte=E_0 \sin \omega te=E0​sinωt i=I0sin⁡(ωt−ϕ)i=I_0 \sin (\omega t-\phi)i=I0​sin(ωt−ϕ) The average power in the circuit over one cycle of AC is

Official previous-year question

Held on 30 Apr 2008 · Verified 9 Jul 2026.

Options

  1. A

    E0I02\frac{E_0 I_0}{2}2E0​I0​​

  2. B

    E0I02sin⁡ϕ\frac{E_0 I_0}{2} \sin \phi2E0​I0​​sinϕ

  3. C

    E0I02cos⁡ϕ\frac{E_0 I_0}{2} \cos \phi2E0​I0​​cosϕ

  4. D

    E0I0E_0 I_0E0​I0​

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