Here C1,C2 and C3 are in series. 
C′1=C1+2C1+3C1 C′1⇒C=6C6+3+2=6C11=116C All the capacitors in branch number 1 is in series so the charge on each number capacitor is: Q′=116CV Also charge on capacitor C4 is Q=4 V ∴ Ratio =QQ′=11×4CV6CV=223