In Bohr's model: $KE = -E$ (total energy is negative)
$$\frac{KE}{E} = \frac{-E}{E} = -1$$
Verified 30 May 2026.
In Bohr's model, the ratio of the kinetic energy to the total energy of the electron in the $n$th orbit is:
$-1$
$1$
$-2$
$2$
In Bohr's model: $KE = -E$ (total energy is negative)
$$\frac{KE}{E} = \frac{-E}{E} = -1$$
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
The work function of a metal is 4.2 eV. The threshold wavelength for photoelectric emission is approximately:
The de Broglie wavelength of a particle with mass m and velocity v is:
The work function of a metal is 4.2 eV. What is the threshold wavelength for photoelectric emission? (hc = 1240 eV·nm)
The work function of a metal is 4.2 eV. The threshold wavelength is (hc = 1240 eV·nm):
The de Broglie wavelength of a particle with momentum p is