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The minimum frequency of photon required to break a particle of mass 15.348 amu into 4 α particles is ____ kHz. [mass of He nucleus = 4.002 amu, 1…

JEE Main 2026 — Physics Modern Physics

2026mcqmedium

The minimum frequency of photon required to break a particle of mass 15.348 amu into 4α4 \alpha4α particles is ____\_\_\_\_____ kHz.

[mass of He nucleus = 4.002amu,1amu=1.66×10−27 kg, h=6.6×10−34 J.s4.002 \mathrm{amu}, 1 \mathrm{amu}=1.66 \times 10^{-27} \mathrm{~kg}, \mathrm{~h}=6.6 \times 10^{-34} \mathrm{~J}. \mathrm{s}4.002amu,1amu=1.66×10−27 kg, h=6.6×10−34 J.s and c=3×108 m/s\mathrm{c}=3 \times 10^{8} \mathrm{~m} / \mathrm{s}c=3×108 m/s ]

Official previous-year question

Held on 22 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    14.94×101914.94 \times 10^{19}14.94×1019

  2. B

    9×10209 \times 10^{20}9×1020

  3. C

    14.94×102014.94 \times 10^{20}14.94×1020

  4. D

    9×10199 \times 10^{19}9×1019

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