Surface area x∝A2/3
Xi=82/3K=4K
Xf=(8+10+9)2/3K=9K
% increase in surface area of nucleus
xi=4K9K−4K×100=125%
JEE Main 2026 — Physics Modern Physics
An atom 38X is bombarded by shower of fundamental particles and in 10 s this atom absorbed 10 electrons, 10 protons and 9 neutrons. The percentage growth in the surface area of the nucleons is recorded by:
Held on 28 Jan 2026 · Verified 6 Jul 2026.
250%
150%
900%
125%
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