λ1hc=λ0hc+eV ...(i)
λ2hc=λ0hc+3eV ...(ii)
λ3hc=λ0hc+eV′ ....(iii)
Equation (i) and (ii)
2λ13−2λ21=λ01
λ3hc−hc[2λ13−2λ21]=eV′
ehc[λ31−2λ13+2λ21]=V′
JEE Main 2016 — Physics Modern Physics
When photons of wavelength λ1 are incident on an isolated sphere, the corresponding stopping potential is found to be V. When photons of wavelength λ2 are used, the corresponding stopping potential was thrice that of the above value. If light of wavelength λ3 is used then find the stopping potential for this case:
Held on 9 Apr 2016 · Verified 6 Jul 2026.
ehc[λ31+λ21−λ11]
ehc[λ31+2λ21−λ11]
ehc[λ31−λ21−λ11]
ehc[λ31+2λ21−2λ13]
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