21mv2=λhc−ϕ ...(i)
21mv′2=34λhc−ϕ ...(ii)
From Eqn. (i)
λhc=21mv2+ϕ
On putting this Equation (ii)
21mv′2=34(21mv2+ϕ)−ϕ
v′2=34v2+3m2ϕ
⇒v′>34v
Radiation of wavelength λ is incident on a photocell. The fastest emitted photoelectron has a speed v. If the wavelength is changed to 43λ, the speed of the fastest emitted photoelectron will be
Held on 3 Apr 2016 · Verified 6 Jul 2026.
=v(34)21
=v(43)21
>v(34)21
<v(34)21
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