Centripetal acceleration a = ω²R. Given a = 4 m/s² and R = 2 m. So ω² = a/R = 4/2 = 2. Therefore ω = √2 rad/s.
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JEE Main 2024 — Physics Mechanics
easy
mcq
2024
Official previous-year question
Verified 30 May 2026.
Question
A particle moves in a circle of radius R with constant angular velocity ω. If the centripetal acceleration is 4 m/s² when R = 2 m, what is the angular velocity?
Options
- A
1 rad/s
- B
√2 rad/s
- C
2 rad/s
- D
4 rad/s
Solution
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