Since retardation a ∝ x, we have a = -kx. Using v dv/dx = -kx, integrating: v²/2 = -kx²/2 + C. Loss in KE = ½m(v₁² - v²) ∝ x²
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JEE Main 2023 — Physics Mechanics
medium
mcq
2023
Official previous-year question
Verified 30 May 2026.
Question
A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement x is proportional to:
Options
- Ax²
- Beˣ
- Cx
- Dlogₑx
Solution
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