Since retardation a ∝ x, we have a = -kx. Using v dv/dx = -kx, integrating: v²/2 = -kx²/2 + C. Loss in KE = ½m(v₁² - v²) ∝ x²
A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement x is…
JEE Main 2023 — Physics Mechanics
A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement x is proportional to:
Verified 30 May 2026.
Options
- A
x²
- B
eˣ
- C
x
- D
logₑx
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