vₑ = √(2gR) = √(2GM/R) = R√(8πGρ/3). For planet: v = 2R√(8πG(2ρ)/3) = 2√2 × vₑ. Ratio = 1:2√2
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JEE Main 2022 — Physics Mechanics
hard
mcq
2022
Official previous-year question
Verified 30 May 2026.
Question
The ratio of escape velocity on Earth to the escape velocity on a planet whose radius and mean density are twice that of Earth is:
Options
- A1:2
- B1:4
- C1:2√2
- D1:√2
Solution
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