Velocity of the tennis ball on the surface of the earth or ground v=1+R2k22gh( where k= radius of gyration of spherical shell =32R) Horizontal range AB=gv2sin2θ=g1+k2/R22gh)2sin(2×30∘)
A tennis ball (treated as hollow spherical shell) starting from O rolls down a hill. At point A the ball becomes air borne leaving at an angle of 30°…
JEE Main 2013 — Physics Mechanics
2013mcqhard
A tennis ball (treated as hollow spherical shell) starting from O rolls down a hill. At point A the ball becomes air borne leaving at an angle of 30∘ with the horizontal. The ball strikes the ground at B. What is the value of the distance AB ? (Moment of inertia of a spherical shell of mass m and radius R about its diameter =32mR2 ) 
Official previous-year question
Held on 22 Apr 2013 · Verified 6 Jul 2026.
Options
- A
1.87 m
- B
2.08 m
- C
1.57 m
- D
1.77 m
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