Angular momentum L=m(v×r) =2 kg(dtdr×r)=2 kg(4t××5i−2t2j^)=2 kg(−20tk^)=2 kg×−20×2 m−2 s−1k^=−80k^
A particle of mass 2 kg is moving such that at time t, its position, in meter, is given by r(t)=5i^−2t2j^. The angular momentum of the particle at t=2s about the origin in kgm−2 s−1 is :
Held on 23 Apr 2013 · Verified 6 Jul 2026.
−80k^
(10i^−16j^)
−40k^
40k^
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