r×F=l×α 2(20t−5t2)=10α⇒α=4t−t2 dtdω=4t−t2 dω=(4t2−t2)dt ω=2t2−3t3 (on integration) ω=0⇒t=6 s
A pulley of radius 2 m is rotated about its axis by a force F=(20t−5t2) Newton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation made by the pulley before its direction of motion if reversed, is :
Held on 30 Apr 2011 · Verified 6 Jul 2026.
more than 3 but less than 6
more than 6 but less than 9
more than 9
less than 3
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