T2∝R3⇒( T2T1)2=(R2R1)3 ⇒( T2T1)=(R2R1)3/2=(41)3/2⇒ T1T2=(4)3/2=8 ⇒T2=8×T1=8×5=40=40 hours
The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value,…
JEE Main 2003 — Physics Mechanics
The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Options
- A
10 hours
- B
80 hours
- C
40 hours
- D
20 hours
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