I=21mR or M∝t∝R2 For discX,Ix=21(m)(R)2=21(πr2t).(R)2 For disc Y,Iy=21[π(4R)2⋅t/4][4R]2 ⇒IyIx=(4)31⇒Iy=64Ix
A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius 4 R is made from an iron plate of thickness t…
JEE Main 2003 — Physics Mechanics
A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius 4R is made from an iron plate of thickness 4t. Then the relation between the moment of inertia IX and IY is
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Options
- A
IY=32Ix
- B
IY=16Ix
- C
IY=IX
- D
IY=64IX
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