A body travels a distance s in t seconds. It starts from rest and ends at rest. In the first part of the journey, it moves with constant acceleration…
JEE Main 2003 — Physics Mechanics
2003mcqmedium
A body travels a distance s in t seconds. It starts from rest and ends at rest. In the first part of the journey, it moves with constant acceleration f and in the second part with constant retardation r. The value of t is given by
Official previous-year question
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Options
A
2s(f1+r1)
B
2s(f1+r1)
C
f1+r12s
D
2s(f+r)
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Solution
Portion OA, OB corresponds to motion with acceleration ' f ' and retardation ' r ' respectively. Area of △OAB=S and OB=t. Let OL=t1, LB=t2 and AL=v,S=21OB⋅AL=21t⋅v;v=t2S Also, f=t1v,t1=fv=tf2s and r=t2v,t2=rv=tr2s;t=t1+t2=tf2s+tr2st=(f1+r1)t2s⇒t=2s(f1+r1)
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