Number of atoms is calculated as the product of the number of moles, atomicity, and Avogadro's number (NA).
For A: Moles of O2 = 322=161 mol. Atomicity of O2 is 2.
Number of atoms = 161×2×NA=81NA
For B: Moles of SO2 = 644=161 mol. Atomicity of SO2 is 3.
Number of atoms = 161×3×NA=163NA
For C: Moles of O2 at STP = 224001400=161 mol. Atomicity of O2 is 2.
Number of atoms = 161×2×NA=81NA
For D: Moles of He at STP = 22.40.05=4481 mol. Atomicity of He is 1.
Number of atoms = 4481×1×NA=4481NA
For E: Moles of H2 = 0.0625=161 mol. Atomicity of H2 is 2.
Number of atoms = 161×2×NA=81NA
Comparing the number of atoms, A, C, and E contain the same number of atoms.
Answer: A, C and E only
Which of the following contain the same number of atoms ? (Given : Molar mass in g mol^-1 of H, He, O and S are 1, 4, 16 and 32 respectively) A. 2 g…
JEE Main 2026 — Chemistry Physical Chemistry
Which of the following contain the same number of atoms ? (Given : Molar mass in g mol−1 of H, He, O and S are 1,4,16 and 32 respectively)
A. 2 g of O2 gas
B. 4 g of SO2 gas
C. 1400 mL of O2 at STP
D. 0.05 L of He at STP
E. 0.0625 mol of H2 gas
Choose the correct answer from the options given below :
Held on 6 Apr 2026 · Verified 1 Jul 2026.
Options
- A
A and B only
- B
B and C only
- C
C and D only
- D
A, C and E only
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