Mass of H2SO4 solution =50×1.3=65 g
Mass of pure H2SO4=65×10050=32.5 g
Moles of H2SO4=9832.5≈0.3316 mol
Moles of Zn=6520≈0.3077 mol
The balanced chemical equation is:
Zn+H2SO4→ZnSO4+H2
Since the moles of Zn are less than the moles of H2SO4, Zn is the limiting reagent.
Moles of H2 produced = Moles of Zn=6520 mol
Volume of H2 gas at STP =6520×22.4 L=6.892 L
Answer: 6.892 L
What volume of hydrogen gas at STP would be liberated by action of 50 mL of H_2SO_4 of 50% purity (density = 1.3 g mL^-1) on 20 g of zinc ? Given :…
JEE Main 2026 — Chemistry Physical Chemistry
What volume of hydrogen gas at STP would be liberated by action of 50 mL of H2SO4 of 50% purity (density =1.3 g mL−1) on 20 g of zinc ?
Given : Molar mass of H, O, S, Zn are 1,16,32,65 g mol−1 respectively.
Held on 5 Apr 2026 · Verified 1 Jul 2026.
Options
- A
5.824 L
- B
7.428 L
- C
6.892 L
- D
8.375 L
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