10% w/w aqueous urea solution means 10 g of urea is present in 100 g of solution.
Mass of urea =10 g
Mass of water =100−10=90 g
Molar mass of urea (NH2CONH2) =14+2+12+16+14+2=60 g mol−1
Molar mass of water (H2O) =18 g mol−1
Moles of urea, nurea=6010=61 mol
Moles of water, nwater=1890=5 mol
Total moles =5+61=631 mol
Mole fraction of water, xwater=nwater+nureanwater=6315=3130≈0.967
Answer: 0.967