JEE Main 2026 — Chemistry Physical Chemistry

2026integermedium

The temperature at which the rate constants of the given below two gaseous reactions become equal is $\_\_\_\_$ K. (Nearest integer)

$\mathrm{X} \longrightarrow \mathrm{Y} \quad \mathrm{k}_{1}=10^{6} e^{\frac{-30000}{\mathrm{~T}}}$

$\mathrm{P} \longrightarrow \mathrm{Q} \quad \mathrm{k}_{2}=10^{4} e^{\frac{-24000}{\mathrm{~T}}}$

Given: $\ln 10=2.303$

Official previous-year question

Held on 22 Jan 2026 · Verified 6 Jul 2026.

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Solution

To find the temperature at which $k_1 = k_2$ ,

set the rate constant equations equal: $10^6 e^{-30000/T} = 10^4 e^{-24000/T}$ .

Dividing both sides by $10^4$ : $100 = e^{-24000/T + 30000/T} = e^{6000/T}$ .

Taking natural logarithm: $\ln(100) = \frac{6000}{T}$ .

Since $\ln(100) = 2\ln(10) = 2 \times 2.303 = 4.606$ : $4.606 = \frac{6000}{T}$ .

Solving for T: $T = \frac{6000}{4.606} = 1302.5$ K.

Rounding to the nearest integer gives T = 1303 K.

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JEE Main 2026 — Chemistry Physical Chemistry

2026integermedium

The temperature at which the rate constants of the given below two gaseous reactions become equal is $\_\_\_\_$ K. (Nearest integer)

$\mathrm{X} \longrightarrow \mathrm{Y} \quad \mathrm{k}_{1}=10^{6} e^{\frac{-30000}{\mathrm{~T}}}$

$\mathrm{P} \longrightarrow \mathrm{Q} \quad \mathrm{k}_{2}=10^{4} e^{\frac{-24000}{\mathrm{~T}}}$

Given: $\ln 10=2.303$

Official previous-year question

Held on 22 Jan 2026 · Verified 6 Jul 2026.

Did you get this right?

Solution

To find the temperature at which $k_1 = k_2$ ,

set the rate constant equations equal: $10^6 e^{-30000/T} = 10^4 e^{-24000/T}$ .

Dividing both sides by $10^4$ : $100 = e^{-24000/T + 30000/T} = e^{6000/T}$ .

Taking natural logarithm: $\ln(100) = \frac{6000}{T}$ .

Since $\ln(100) = 2\ln(10) = 2 \times 2.303 = 4.606$ : $4.606 = \frac{6000}{T}$ .

Solving for T: $T = \frac{6000}{4.606} = 1302.5$ K.

Rounding to the nearest integer gives T = 1303 K.

Your note

JEE Main Physical Chemistry in other years

Keep practicing Physical Chemistry

Work through every JEE Main Physical Chemistry PYQ, year by year.

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JEE Main 2026 — Chemistry Physical Chemistry

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Solution

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JEE Main Physical Chemistry in other years

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Organic Chemistry

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JEE Main 2026 — Chemistry Physical Chemistry

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry