Ratio of mass percentage of C : H = 12:1
Ratio of moles of C : H = 1212:11=1:1
The empirical formula is CH. Since the hydrocarbon has two carbon atoms, its molecular formula is C2H2.
Molar mass of C2H2=2×12+2×1=26 g mol−1
Moles of C2H2 in 3.38 g = 263.38=0.13 mol
The combustion reaction is:
C2H2+25O2→2CO2+H2O
From the stoichiometry, 1 mole of C2H2 produces 2 moles of CO2.
Moles of CO2 produced = 2×0.13=0.26 mol
Molar mass of CO2=12+2×16=44 g mol−1
Weight of CO2 formed = 0.26×44=11.44 g
Answer: 11.44